NEET
- Exam
- NEET
- Subject
- Chemistry
- Chapter
- Carboxylic Acid Derivatives
NEET · Chemistry · Carboxylic Acid Derivatives
Match the column ( Column-I (Transformations) Column-II (Reagents)...
Match the column
(
)
| Column-I (Transformations) | Column-II (Reagents) | ||
| (a) | Allyl alcohol to propenal | (p) | K_2 Cr_2 O_7 / H^{\oplus} |
| (b) | Ethane nitrile to ethanal | (q) | O_3 / H_2 O-Zn dust |
| (c) | 1-hexanol to hexanoic acid | (r) | PCC |
| (d) | 2-Butene to ethanal | (s) | DIBAL-H |
Options
- A
- B(, , , )
- C(, , , )
- D(, , , )
Correct answer
C. (, , , )
Step-by-step solution
- (a) Allyl alcohol (\rightarrow) propenal (\rightarrow(\mathrm{r})) PCC
PCC oxidizes a (1^{\circ}) alcohol to an aldehyde without over-oxidation.
- (b) Ethanenitrile (\rightarrow) ethanal (\rightarrow) (s) DIBAL-H
DIBAL-H partially reduces nitriles to aldehydes.
- (c) 1-Hexanol (\rightarrow) hexanoic acid (\rightarrow) (p) (\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 / \mathrm{H}^{+})
Strong oxidation of a (1^{\circ}) alcohol to a carboxylic acid.
- (d) 2-Butene (\rightarrow) ethanal (\rightarrow) (q) (\mathrm{O}_3 / \mathrm{H}_2 \mathrm{O}-\mathrm{Zn}) (ozonolysis)
Reductive workup gives aldehydes.