NEETChemistryAmines
A hydrocarbon ‘A’, (C 4 H 8 ) on reaction with HCl gives a compound ‘B’, (C 4 H 9 Cl), which on reaction with 1 mol of NH 3 gives compound ‘C’, (C 4 H 11 N). On reacting with NaNO 2 and HCl followed by treatment with water, compound ‘C’ yields an optically active alcohol, ‘D’. Ozonolysis of ‘A’ gives 2 mols of acetaldehyde. Identify compounds ‘C’ and ‘D’.
Options
- AC = Butan-2-amine and D = Butan-1-ol
- BC = Butan-2-amine and D = Butan-2-ol
- CC = Butan-3-amine and D = Butan-2-ol
- DC = Butan-3-amine and D = Butan-1-ol
Correct answer
B. C = Butan-2-amine and D = Butan-2-ol
Step-by-step solution
Correct Option is : (B) C = Butan-2-amine and D = Butan-2-ol