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NEETChemistryAmines

Read the following statements regarding the electrophilic aromatic substitution reactions of aniline: (A) It does not undergo Friedel-Crafts alkylation due to salt formation with aluminium chloride. (B) Direct nitration yields a significant amount of m -nitroaniline. (C) The anilinium ion formed in strongly acidic medium is an activating group. (D) Monobromination requires protection of the - NH ₂ group by acetylatio

Options

  1. A(A), (B), (C) and (D)
  2. B(A) and (D) only
  3. C(B) and (C) only
  4. D(A), (B) and (D) only

Correct answer

D. (A), (B) and (D) only

Step-by-step solution

Statement (A) is correct: Aniline forms a salt with the Lewis acid catalyst ( AlCl ₃ ), which acts as a strongly deactivating group, preventing Friedel-Crafts reactions. Statement (B) is correct: During direct nitration in a strongly acidic medium, aniline is protonated to form the anilinium ion, which directs the incoming electrophile to the meta position, yielding about 47% m -nitroaniline. Statement (C) is incorrect: The anilinium ion ( - NH ₃^+ ) is a strongly deactivating group, not an activating group. Statem

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