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NEETChemistryAmines

Ethanamine is heated with chloroform and ethanolic potassium hydroxide to form an intermediate A. The intermediate A is then reduced using lithium aluminium hydride to form the major product B. The IUPAC name of the major product B is:

Options

  1. APropan-1-amine
  2. BN-Methylethanamine
  3. CN-Methylmethanamine
  4. DEthanamine

Correct answer

B. N-Methylethanamine

Step-by-step solution

Ethanamine ( CH₃CH₂NH₂ ), being a primary aliphatic amine, undergoes the carbylamine reaction when heated with chloroform and ethanolic potassium hydroxide. This produces ethyl isocyanide ( CH₃CH₂NC ) as intermediate A. Reduction of ethyl isocyanide with lithium aluminium hydride ( LiAlH₄ ) yields a secondary amine, N-methylethanamine ( CH₃CH₂NHCH₃ ), as the major product B. If the intermediate were incorrectly assumed to be a nitrile, it would reduce to propan-1-amine, but the carbylamine reaction specifically pro

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