NEETChemistryAmines
Match List I with List II. List I List II (A) Propan-2-amine (I) Hinsberg's reagent (B) N-methylethanamine (II) Forms an alkali-insoluble solid with Hinsberg's reagent (C) N,N-dimethylmethanamine (III) Does not react with Hinsberg's reagent to form a sulphonamide (D) Benzenesulphonyl chloride (IV) Forms an alkali-soluble solid with Hinsberg's reagent Choose the correct answer from the options given below:
Options
- A(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
- B(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
- C(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
Correct answer
B. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
Step-by-step solution
(A) Propan-2-amine ( CH₃CH(NH₂)CH₃ ) is a primary ( 1^ ) amine. It reacts with Hinsberg's reagent to form a sulphonamide containing an acidic hydrogen, which dissolves in alkali. Hence, (A) matches with (IV). (B) N-methylethanamine ( CH₃NHCH₂CH₃ ) is a secondary ( 2^ ) amine. It reacts with Hinsberg's reagent to form a sulphonamide that lacks an acidic hydrogen, making it insoluble in alkali. Hence, (B) matches with (II). (C) N,N-dimethylmethanamine ( (CH₃)₃N ) is a tertiary ( 3^ ) amine. It does not react with Hin