A coil of inductance 8 H is connected to a capacitor of capacitance 0.02 F . To what wavelength is this circuit tuned?

Step-by-step solution

aligned & Here, L=8 H =8 10⁻⁶ H ; & C=0.02 F =0.02 10⁻⁶ ~F & Resonant frequency, & f_r= 1 2 L C = 1 2 8 10⁻⁶ 0.02 10⁻⁶ & =3.98 10^5 ~Hz & aligned If c (=3 10^8 ~m ~s ⁻¹ ) is the velocity of the electromagnetic wave, then, Wavelength, = c f = 3 10^8 3.98 10^5 =7.54 10^2 ~m