If maximum energy is stored in capacitor at t=0 , then find the time after which current in the circuit will be maximum

Step-by-step solution

In L-C oscillations, total time in one complete cycle is, T=2 L C aligned & T=2 25 10⁻³ 10 10⁻⁶ & T=2 25 10⁻⁸ & = 10⁻³ sec aligned After time T / 4 capacitor is fully discharged and current in circuit will be maximum, then T 4 = 10⁻³ 4 = 4 ~ms