AIIMS2018PhysicsCapacitance
A fully charged parallel plate capacitor of 1 F capacity is discharging through a resistor. If the energy of the capacitor reduces to half in one second then the value of resistance will be
Options
- A2 10^6 2
- B2 10^3 2
- C10^6 2
- D10^3 2
Correct answer
A. 2 10^6 2
Step-by-step solution
As Q=Q₀ e^ -t / . When energy is 50 % then Q= Q₀ 2 aligned & Q₀ 2 =Q₀ e^ -t / & e^ t / = 2 & t = ( 2 ) = t ( 2 ) & R C= 2 2 & R= 2 C 2 = 2 10⁻⁶ 2 = 2 10^6 2 aligned