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AIIMS 2017

Exam: AIIMS
Year: 2017
Subject: Physics
Chapter: Current Electricity

AIIMS 2017 · Physics · Current Electricity

The measurement of voltmeter in the following circuit is

The measurement of voltmeter in the following circuit is

The measurement of voltmeter in the following circuit is

Options

A $2.25 \mathrm{~V}$
B $4.25 \mathrm{~V}$
C $2.75 \mathrm{~V}$
D $6.25 \mathrm{~V}$

Correct answer

A. $2.25 \mathrm{~V}$

Step-by-step solution

Resistance of voltmeter and

60 \Omega

are in parallel.

\therefore \quad

Equivalent resistance

=\frac{60 \times 40}{60+40}=\frac{60 \times 40}{100}=24 \Omega

For the whole circuit, current

I=\frac{6 \mathrm{ V}}{(40+24) \Omega}=\frac{6}{64}=\frac{3}{32} \mathrm{ A} The voltmeter reads potential difference across

60 \Omega

.

\begin{aligned} & \therefore \quad \text{ Voltmeter reading }=I \times R_{e q} \\ & \qquad=\frac{3}{32} \times 24=\frac{9}{4} \mathrm{ V}=2.25 \mathrm{ V}\end{aligned}

$$

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