Exam

AIIMS

Year

2010

Subject

Physics

Chapter

Current Electricity

AIIMS 2010 · Physics · Current Electricity

In the circuit shown, current flowing through 25 ~V cell is

In the circuit shown, current flowing through $25 \mathrm{~V}$ cell is

Step-by-step solution

Applying $K V L$ in loop $A B C D A, A B F E A, A B G H A and A B I I A$, we get $$\begin{aligned}& 30-i_1 \times11=-25 \\ & 20+i_2 \times5=25 \\ & 5-i_3 \times10=-25 \\ & 10+i_4 \times5=25 \end{aligned}$$Solving equations (i), (ii), (iii)$and (iv) we geti_1=5 \mathrm{~A}, i_2=1 \mathrm{~A}, i_3=3 \mathrm{~A} and i_4=3 \mathrm{~A}$. Hence, current flowing through $25 \mathrm{~V}$ cell is $12 \mathrm{~A}.