AP EAMCET202422 May 2024Evening ShiftPhysicsAlternating CurrentActual
In the circuit shown in the figure, neglecting the source resistance, the voltmeter and ammeter readings respectively are
Options
- A0 ~V , 8 ~A
- B150 ~V , 3 ~A
- C150 ~V , 6 ~A
- D0 ~V , 3 ~A
Correct answer
A. 0 ~V , 8 ~A
Step-by-step solution
R =30 , X _ L =25 , X _ C =25 Z = ( X _ L - X _ C )^2+ R ^2 =30 Reading of ammeter, I_ rms = V _ rms Z = 240 30 =8 ~A Reading of voltmeter, V = I _ rms ( X _ L - X _ C )^2 =8 (25-25)^2 =0 V