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AP EAMCET202422 May 2024Morning ShiftPhysicsAlternating CurrentActual

A 50 Hz AC circuit has a 10 mH inductor and a 2 resistor in series. The value of capacitance to be placed in series in the circuit to make the circuit power factor as unity is

Options

  1. A1.014 10⁻⁶ ~F
  2. B1.014 10⁻³ ~F
  3. C2.6 10⁻³ ~F
  4. D4.125 10⁻³ ~F

Correct answer

B. 1.014 10⁻³ ~F

Step-by-step solution

For power factor, =1 , the LCR circuit is in resonance. aligned & w = 1 LC 2 f = 1 LC & 2 50= 1 10 10⁻³ C & C =1.014 10⁻³ ~F aligned

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