An inductor and a resistor are connected in series to an ac source of voltage 144 (100 t+ 2 ) Volt. If the current in the circuit is 6 (100 t+ 6 ) ampere, then the resistance of the resistor is

Step-by-step solution

In LR circuit, aligned & V=144 (100 t+ 2 ) & I=6 (100 t+ 6 ) aligned Also, = X_L R ( 2 - 6 )= X_L R 3 = X_L R X_L= 3 R Now, I₀= V₀ z 6= 144 R^2+X_L^2 = 144 R^2+( 3 R)^2 R =12