A resistance of 20 is connected to a source of an alternating potential V =200 (10 t ) . If t is the time taken by the current to change from the peak value to rms value, then ' t ' is (in seconds).

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Correct answer: D. 2.5 10⁻²

R =20 , ~V =200 (10 t ) I= V R =10 (10 t) ....(i) I _ o =10, I _ rms = I _ o 2 = 10 2 From equation (i), 10=10 (10 t₁ ) (10 t₁ )= 2 t₁= 1 20 s Again, 10 2 =10 (10 t ₂ ) (10 t ₂ )= 4 t ₂= 1 40 ~s t=t₁-t₂= 1 20 - 1 40 = 1 40 =2.5 10⁻² ~s

A resistance of 20 is connected to a source of an alternating potential V =200 (10 t ) . If t is the time taken by the current to change from the peak value to rms value, then ' t ' is (in seconds).

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