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AP EAMCET20228 Jul 2022Evening ShiftPhysicsAlternating CurrentActual

An inductor of reactance 1 and a resistor of resistance 3 are connected in series to the terminals of 10 ~V (rms) AC source. The power dissipated in the circuit is

Options

  1. A33.3 ~W
  2. B30 ~W
  3. C31.6 ~W
  4. D20 ~W

Correct answer

B. 30 ~W

Step-by-step solution

Average power dissipated. P_ avg = v_ rms ^2 R z^2 Here, Z= impedance = X_L^2+R^2 where, X_L= inductive reactance =L So impedance, z= X_L^2+R^2 = 1^2+3^2 (Here given, X_L=1 and R=3 ) So, z= 10 Given ; V_ rms =10 ~V so, aligned P_ avg & = V_ rms ^2 R z^2 = 100 3 10 & =30 ~W aligned

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