AP EAMCET20225 Jul 2022Morning ShiftPhysicsAlternating CurrentActual
An R-L-C circuit consists of a 150 resistor, 20 F capacitor and a 500 mH inductor connected in series with a 100 ~V AC supply. The angular frequency of the supply voltage is 400 rad s ⁻¹ . The phase angle between current and the applied voltage is
Options
- A⁻¹(0.8)
- B⁻¹(0.25)
- C⁻¹(0.6)
- D⁻¹(0.5)
Correct answer
D. ⁻¹(0.5)
Step-by-step solution
In R-L-C series circuit aligned R=150 , C & =20 F & =2 10⁻⁵ ~F aligned L=500 mH =0.5 H Supply voltage, V=100 ~V Angular frequency, =400 rads ⁻¹ Now, X_L= L=400 0.5=200 _C= 1 C = 1 400 2 10⁻⁵ X_C=125 _L>X_C = X_L-X_C R = 200-125 150 = 75 150 =0.5 = ⁻¹(0.5)