AP EAMCET201923 Apr 2019Morning ShiftPhysicsAlternating CurrentActual
In the given circuit, the angular frequency of the voltage source is (70 10^3 rad s ⁻¹ ). The circuit effectively behaves like,
Options
- Apurely resistive circuit
- Bseries RL circuit
- Cseries (R C ) circuit
- Dseries (L C ) circuit with (R=0 )
Correct answer
C. series (R C ) circuit
Step-by-step solution
Given, (L=10 H ), (C=1 F , R=10 ) and angular frequency, ( =70 10^3 rad s ⁻¹ ) Now, the impedance of series LCR circuit, ( gathered Z= R^2+ ( L- 1 C )^2 Z= 10^2+ [70 10⁺³ 10 10⁻⁶- 1 70 10⁺³ 1 10⁻⁶ ] Z= 100+ [0.7- 100 7 ]^2 Z= 100+(-1358)^2 gathered ) Here, negative sign shows that the circuit properties are more likely to be capacitive than the inductive i.e., ( X_C > X_L ) So, the circuit behaves like series (R C ) circuit. Hence, the correct option is (c).