A resistor and an inductor are connected in series to an AC source of voltage 150 (100 t+ ) volt. If the current in the circuit is 5 (100 t+ 2 3 ) ampere, then the average power dissipated and the resistance of the resistor are respectively

Step-by-step solution

Given, peak voltage, V₀=150 ~V Peak current, I₀=5 Phase difference between voltage and current, = - 2 3 = 3 =60^ Now, average power in R-L circuit, aligned P_ av =V_ rms & I_ rms & = V₀ 2 I₀ 2 60^ = 150 2 5 2 1 2 P_ av = & 187.5 ~W aligned gathered Impendence, Z= V₀ I₀ = 150 5 Z=30 R Z = R 30 = 60^ R=30 1 2 R=15 gathered