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AP EAMCET201822 Apr 2018Morning ShiftPhysicsAlternating CurrentActual

For the AC circuit shown below, phase difference between emf and current is 4 radian as shown in the graph. If the impedance of the circuit is 1414 , then the values of P and Q are

Options

  1. A1 k , 10 F
  2. B1 k , 1 F
  3. C1 k , 10 mH
  4. D1 k , 1 mH

Correct answer

A. 1 k , 10 F

Step-by-step solution

In the shown figure, current is ahead of voltage, so its a R C circuit, so P is a resistor and Q is a capacitor. Now, in R C circuit, Z= R^2+X_C^2 For simple solution, Given aligned & =1000 2 & =1000 1+1 & = (1000)^2+(1000)^2 X_C & =1000 R=1000 Now, X_C & = 1 C C= 1 X_C & & = 1 100 1000 =10 F aligned Z=1414=1000 1.414

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