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AP EAMCET202421 May 2024Evening ShiftPhysicsAtomic PhysicsActual

The electrostatic potential energy of the electron in an orbit of hydrogen is -6.8 eV . The speed of the electron in this orbit is ( C is speed of light in vacuum)

Options

  1. AC 137
  2. BC 274
  3. C2 C 137
  4. D3 C 137

Correct answer

B. C 274

Step-by-step solution

U =-6.8 eV Total energy, E _ n = U 2 = -6.8 2 =-3.4 eV -13.6 n ^2 =-3.4 n =2 Speed, v _ n = ( C 137 ) 1 n for n =2, v ₂= ( C 137 ) 1 2 = C 274

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