The frequency of the light emitted when an electron comes down from n=4 to n=2 level in hydrogen atom is 3 7 times of the following transition of the Li atom

Step-by-step solution

We have 1 = R _ H Z ^2 ( 1 n ₁^2 - 1 n ₂^2 ) aligned & hc = hc _ H Z ^2 ( 1 n ₁^2 - 1 n ₂^2 ) & E _ n ₂ n ₁ =13.6 Z ^2 ( 1 n ₁^2 - 1 n ₂^2 ) eV aligned For hydrogen E_ 4 2 =13.6 1^2 ( 1 2^2 - 1 4^2 )=13.6 ( 1 4 - 1 16 )=13.6 ( 4-1 16 )= 13.6 3 16 =2.55 eV For Lithium E _ n ₂ n ₁ = 3 7 2.55 eV =1.09 eV So, 13.6 3^2 ( 1 n ₁^2 - 1 n ₂^2 )=1.09 None of the value of n₂ and n₁ satisfy the above equation. So this a none.