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AP EAMCET20225 Jul 2022Morning ShiftPhysicsAtomic PhysicsActual

An electron in the hydrogen atom excites from 2 nd orbit to 4 th orbit then the change in angular momentum of the electron is (Planck's constant h=6.64 10⁻³⁴ ~J - s )

Options

  1. A2.11 10⁻³⁴ ~J - s
  2. B1.05 10⁻³⁴ ~J - s
  3. C0.57 10⁻³⁴ ~J - s
  4. D4.22 10⁻³⁴ ~J - s

Correct answer

A. 2.11 10⁻³⁴ ~J - s

Step-by-step solution

Change in angular momentum of the electron in H -atom when it is excited from 2nd orbit to 4 th orbit is given as L=L₂-L₁ Where, L₂ is angular momentum of 4 th excited state (n=5) and L₁ is angular moment of 2 nd excited ștate (n=3) . L= n₂ h 2 - n₁ h 2 aligned & = h 2 [n₂-n₁ ]= 6.64 10⁻³⁴ 2 3.14 [5-4] & =2.11 10⁻³⁴ ~J - s aligned

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