Energy of a stationary electron in the hydrogen atom is E = - 13 . 6 n 2 eV then the energies required to excite the electron in hydrogen atom to (a) its second excited state and (b) ionized state respectively

Step-by-step solution

(a) For Hydrogen atom, For ground state, n = 1 , energy is E 1 = - 13 . 6 1 2 = - 13 . 6   eV For second excited state, n = 3 , Energy is E 2 = - 13 . 6 3 2 = - 1 . 5   eV Energy required is ∆ E = E 2 - E 1 = - 1 . 5 + 13 . 6 = 12 . 1   eV ≈ 12   eV (b) lonization energy is defined for ground state only, so ionized stated energy = - E 1 = 13 . 6   eV