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AP EAMCET202318 May 2023Evening ShiftPhysicsCapacitanceActual

Eight drops of mercury, each of same radius and same charge combine to form a bigger drop. The ratio of capacitance of the bigger drop to that of each smaller drop is

Options

  1. A8: 1
  2. B4: 1
  3. C2: 1
  4. D1: 1

Correct answer

C. 2: 1

Step-by-step solution

Number of drops, n =8 Let, r is radius of smaller drop and R is the radius of Bigger drop. Volume of smaller drops & bigger drop remains same 8 4 3 r^3= 4 3 r^3 R=2 r Capacitance of spherical conductor, C=4 ₀ R Ratio of capacitance of bigger drop to smaller drop is given as C C ^ = 4 ₀ R 4 ₀ r = R r = 2 r 4 =2: 1 C C^ = 2 1

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