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MHT CET202620 April 2026Morning ShiftPhysicsCapacitanceActual

In a parallel plate air capacitor of plate separation ' d ', a dielectric slab of thickness ' t ' is introduced between the plates. The capacitance becomes one-third of the original value. The dielectric constant of the slab will be

Options

  1. At d + t
  2. Bt 2d + t
  3. Ct d - 2t
  4. D2t 2d - t

Correct answer

B. t 2d + t

Step-by-step solution

The capacitance of a parallel plate air capacitor is given by: C₀ = ₀ A d When a dielectric slab of thickness t and dielectric constant K is introduced between the plates, the new capacitance becomes: C = ₀ A d - t + t K According to the given condition, the new capacitance is one-third of the original value: C = C₀ 3 Substituting the expressions for C and C₀ : ₀ A d - t + t K = ₀ A 3d Equating the denominators: d - t + t K = 3d Rearranging the terms to solve for K : t K = 2d + t K = t 2d + t Answer: t 2d + t

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