MHT CET202619 April 2026Evening ShiftPhysicsCapacitanceActual
A parallel plate air capacitor has capacity 'C' farad, potential 'V' volt and energy 'E' joule. When the gap between the plates is completely filled with dielectric
Options
- AV increases, E decreases.
- BV decreases, E increases.
- Cboth V and E increase.
- Dboth V and E decrease.
Correct answer
D. both V and E decrease.
Step-by-step solution
Since the capacitor is isolated, the charge Q on the plates remains constant. The initial capacitance is C , potential is V = Q C , and energy is E = Q^2 2C . When a dielectric of dielectric constant K > 1 is introduced, the new capacitance becomes C' = KC . The new potential is V' = Q C' = Q KC = V K . Since K > 1 , V' The new energy is E' = Q^2 2C' = Q^2 2KC = E K . Since K > 1 , E' Therefore, both V and E decrease. Answer: both V and E decrease.