AP EAMCET20227 Jul 2022Morning ShiftPhysicsCapacitanceActual
In a parallel plate capacitor, if 10¹² electrons pass from one plate to another, a potential difference of 10 ~V is developed across the plates. The capacitance of the capacitor is
Options
- A0.16 10⁻⁸ ~F
- B1.6 10⁻⁸ ~F
- C16 10⁻⁸ ~F
- D0.8 10⁻⁸ ~F
Correct answer
B. 1.6 10⁻⁸ ~F
Step-by-step solution
Charge on each plate of capacitor has a magnitude, Q=N . e Here, N=10¹², e=1.6 10⁻¹⁹ Potential difference between plates, V=10 ~V Capacitance of capacitor, C= Q V C= N e V = 10¹² 1.6 10⁻¹⁹ 10 =1.6 10⁻⁸ ~F