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AP EAMCET20226 Jul 2022Evening ShiftPhysicsCapacitanceActual

A capacitor of capacitance C₁=10 F to charged using 9 ~V battery. It is then removed from the battery and connected to another capacitor C₂=20 F as shown in the figure. The charge on C₂ after equilibrium has reached is

Options

  1. A6.0 10⁻⁵ C
  2. B60 10⁻⁶ C
  3. C3.0 10⁻⁵ C
  4. D3.0 10⁻⁶ C

Correct answer

A. 6.0 10⁻⁵ C

Step-by-step solution

Given, aligned C₁ & =10 F & =10⁻⁵ ~F V₁ & =9 ~V aligned Charge on capacitor C₁ , aligned q₁ & =C₁ V₁ & =9 10⁻⁵ C C₂ & =20 F =2 10⁻⁵ ~F aligned when uncharged capacitor C₂ is connected with charged capacitor C₁ , then charges will flow from capacitor C₁ to C₂ till both gain the same potential i.e common potential. aligned & Common potential, V= total charge total capacitance & = q₁ C₁+C₂ = 9 10⁻⁵ 10⁻⁵+2 10⁻⁵ & = 9 10⁻⁵ 3 10⁻⁵ =3 ~V aligned Charge on capacitor C₂, q₂=C₂ V =2 10⁻⁵ 3=6 10⁻⁵ C

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