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AP EAMCET20224 Jul 2022Morning ShiftPhysicsCapacitanceActual

A capacitor of capacitance C 1 = 1 μ F is charged using a 9 V battery. C 1 is then removed from the battery & connected to capacitors C 2 and C 3 of 2 μ F and 3 μ F respectively as shown in the figure. Find the charge on C 3 after equilibrium has reached is

Options

  1. A4 . 5 × 10 - 6 C
  2. B3 . 5 × 10 - 6 C
  3. C2 . 5 × 10 - 6 C
  4. D1 . 5 × 10 - 5 C

Correct answer

A. 4 . 5 × 10 - 6 C

Step-by-step solution

Initially, when C 1 is connected with 9   V the charge on it will be, q 0 = C 1 V = 9   μC . Later all the capacitors are connected in parallel. Therefore, the potential difference between the capacitors will be equal. If the charges on them are q 1 ,   q 2   and   q 3 . Then by conservation of charge, q 1 + q 2 + q 3 = q 0 = 9   μC   ⋯ 1 And q 1 C 1 = q 2 C 2 = q 3 C 3 ⇒ q 1 1 = q 2 2 = q 3 3   ⋯   2 Using the above two equations we get q 3 =

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