AP EAMCET202125 Aug 2021Morning ShiftPhysicsCapacitanceActual
Two capacitors each having a capacitance 2 10⁻⁶ ~F and a breakdown voltage 5000 ~V , are joined in series. What will be the resultant capacitance and the breakdown voltage of the combination?
Options
- A4 10⁻⁶ ~F and 1000 ~V
- B10⁻⁶ ~F and 10000 ~V
- C2 10⁻⁶ ~F and 5000 ~V
- D10⁻⁶ ~F and 2500 ~V
Correct answer
B. 10⁻⁶ ~F and 10000 ~V
Step-by-step solution
Given, capacitance C=2 10⁻⁶ ~F Potential difference break down voltage, V=5000 ~V Capacitance in series, 1 C_S = 1 C + 1 C aligned 1 C_S & = ( 1 2 + 1 2 ) 1 10⁻⁶ C_S & =10⁻⁶ ~F aligned Potential difference break down voltage in series, aligned V_S & =V₁+V₂ & =5000+5000=10000 ~V aligned