The equivalent capacitance between A and B in the given circuit is

Step-by-step solution

According to question, As we know that, Series equivalent capacitance, 1 C_ cq = 1 C_a + 1 C_b + 1 C_c + and parallel equivalent capacitance, C_ cq =C_a+C_b+C_c+ Now, since C₄ and C₅ are in parallel. So, their equivalent capacitance, C_a=2+1=3 F Now C_a, C₃ and C₆ are in series will give equivalent capacitance, aligned & & 1 C_b = 1 C_a + 1 C₃ + 1 C₆ = 1 3 + 1 3 + 1 3 = 3 3 =1 & C_b=1 F & aligned Again C_C and C₈ in parallel will give, aligned C_c & =C_b+C₈ & =1+2=3 F aligned Again C₆, C₂ and C₇ are in series will