AP EAMCET202119 Aug 2021Evening ShiftPhysicsCapacitanceActual
Four capacitors with capacitances C 1 = 1 μF , C 2 = 1 . 5 μF , C 3 = 2 . 5 μF and C 4 = 0 . 5 μF are connected as shown and are connected to a 30 volt source. The potential difference between points a and b is:
Options
- A5   V
- B9   V
- C10   V
- D13   V
Correct answer
D. 13   V
Step-by-step solution
Let q be the charge on capacitors C 1 and C 2 ⇒ q C 1 + q C 2 = 30 ⇒ q 1 + q 1 . 5 = 30 ⇒ q = 18   μC V A - V a = q C 1 = 18   V Let q ' be the charge on capacitors C 3 and C 4 ⇒ q ' C 3 + q ' C 4 = 30 ⇒ q ' 2 . 5 + q ' 0 . 5 = 30 ⇒ q ' = 25 2   μC V A - V b = q ' C 3 = 5   V ⇒ V a - V b = V A - V b - V A - V a ⇒ V a - V b = 5 - 18 ⇒ V a - V b = - 13   V