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AP EAMCET202021 Sep 2020Morning ShiftPhysicsCapacitanceActual

A (100 ~V ) battery is connected across the series combination of the two capacitors of (4 F ) and (8 F ). The energy stored in the series combination is

Options

  1. A(0.75 10⁻² ~J )
  2. B(1.33 10⁻² ~J )
  3. C(0.5 ~J )
  4. D(1 ~J )

Correct answer

B. (1.33 10⁻² ~J )

Step-by-step solution

Potential difference across terminals of battery, (V=100 ~V ) Equivalent capacitance of series combination is given as ( aligned & 1 C = 1 C₁ + 1 C₂ = 1 4 + 1 8 = 2+1 8 & 1 C = 3 8 C= 8 3 F aligned ) Same charge will be flow in series combination which is given as ( aligned q & =C V= 8 3 10⁻⁶ 100 & = 8 3 10⁻⁴ C aligned ) ( ) Energy stored, (E= 1 2 q^2 C ) ( aligned & = 1 2 ( 8 3 10⁻⁴ )^2 8 3 10⁻⁶ = 4 3 10⁻² ~J E & =1.33 10⁻² ~J aligned )

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