AP EAMCET202017 Sep 2020Evening ShiftPhysicsCapacitanceActual
Three capacitors of capacitances (C₁=2 F ), (C₂=3 F ) and (C₃=5 F ) are connected in series. A potential difference of (155 ~V ) is applied across the combination. Choose the correct option.
Options
- ALeast potential difference is across (C₃ ). Equivalent capacitance of combination is ( ( 30 31 ) F ). The volt
- BLeast potential difference is across (C₁ ). Equivalent capacitance of combination is ( ( 30 51 ) F ). The volt
- CLeast potential difference is across (C₁ ). Equivalent capacitance of combination is ( ( 30 31 ) F ). The volt
- DLeast potential difference is across ( C ₂ ). Equivalent capacitance of combination is ( ( 30 31 ) F ). The vo
Correct answer
A. Least potential difference is across (C₃ ). Equivalent capacitance of combination is ( ( 30 31 ) F ). The volt
Step-by-step solution
The given situation is shown in the following figure. Equivalent capacitance is given as ( 1 C = 1 C₁ + 1 C₂ + 1 C₃ = 1 2 + 1 3 + 1 5 = 31 30 C= 30 31 F ) In series combination of capacitances, charge flowing through each capacitor is same which is given by ( aligned q & =C V & = 30 31 155=150 C =1.5 10⁻⁴ C aligned ) ( ) Potential difference across (C₁ ), ( aligned V₁ & = q C₁ = 1.5 10⁻⁴ 2 10⁻⁶ =0.75 10^2 V₁ & =75 ~V aligned ) Potential difference across (C₂ ), ( aligned V₂ & = q C₂ = 1.5 10⁻⁴ 3 10⁻⁶ =0.5 10^2 V₂ &