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AP EAMCET201921 Apr 2019Evening ShiftPhysicsCapacitanceActual

In the given circuit, the current through 2 Ω resistor is

Options

  1. A9   A
  2. B0 . 9   A
  3. C1 9   A
  4. D1 0 . 9   A

Correct answer

B. 0 . 9   A

Step-by-step solution

At the steady state, the capacitor behaves as open circuit. The figure below represents the simple circuit, Apply Kirchhoff law in loop I, - 6 + 3 I 1 + I 2 + 2 . 8 I 1 = 0 5 . 8 I 1 - 3 I 2 = 6       . . . . 1 Apply Kirchhoff law in loop II, 2 I 2 + 3 I 2 - I 1 = 0       . . . . 2 From equation 1 and 2 I 2 = 0 . 9   A Thus, the current in 2   Ω resistor is 0 . 9   A .

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