AP EAMCET2012PhysicsCapacitance
A parallel plate capacitor has a capacity 80 10⁻⁶ ~F , when air is present between the plates. The volume between the plates is then completely filled with a dielectric slab of dielectric constant 20. The capacitor is now connected to a battery of 30 ~V by wires. The dielectric slab is then removed. Then, the charge that passes now through the wire is
Options
- A45.6 10⁻³ C
- B25.3 10⁻³ C
- C120 10⁻³ C
- D125 10⁻³ C
Correct answer
A. 45.6 10⁻³ C
Step-by-step solution
Charge that through the wire aligned q & = C V & = (C^ -C ) V & =(k-1) V & =(20-1) (80 10⁻⁶ )(30) & =4.56 10⁻² & =45.6 10⁻³ C aligned