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AP EAMCET2006PhysicsCapacitance

A oil drop having a mass 4.8 10⁻¹⁰ ~g and charge 2.4 10⁻¹⁸ C stands still between two charged horizontal plates separated by a distance of 1 ~cm . If now the polarity of the plates is changed, instantaneous acceleration of the drop is : (g=10 ~ms ⁻² )

Options

  1. A5 ~ms ⁻²
  2. B10 ~ms ⁻²
  3. C15 ~ms ⁻²
  4. D20 ~ms ⁻²

Correct answer

B. 10 ~ms ⁻²

Step-by-step solution

a= F m = q E m = m g m g=10 ~m / s ^2

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