Current sensitivities of two galvanometers G ₁ and G ₂ of resistances 100 and 50 are 10^8 div / A and 0.5 10^5 div / A respectively. The galvanometer in which the voltage sensitivity is more is

Step-by-step solution

G ₁=100 , G ₂=50 I _ S 1 =10^8 div / A , I _ S 2 =0.5 10^5 div / A Voltage sensitivity, V_S= I_S G aligned & V _ S 1 = I _ S 1 G ₁ = 10^8 100 =10^6 ~V / div & ~V _ S 2 = I _ S 2 G ₂ = 0.5 10^5 50 =10^3 ~V / div & ~V ₅₁ V ₅₂ aligned