AP EAMCET202421 May 2024Evening ShiftPhysicsCurrent ElectricityActual
The charge q (in coulomb) passing through a 10 ~ohm resistor as a function of time t (in second) is given by q=3 t^2-2 t+6 . The potential difference across the ends of the resistor at time t=5 ~s is
Options
- A120 V
- B240 V
- C140 V
- D280 V
Correct answer
D. 280 V
Step-by-step solution
aligned & q =3 t ^2-2 t +6 & aligned & Current, I = dq dt = d dt (3 t ^2-2 t +6 ) & =(6 t -2) & A t t =5 ~s , I =6 5-2=28 ~A & ~V = IR =28 10=280 ~V aligned aligned