A 8 resistor is connected to a battery that has an internal resistance of 0.2 . If the voltage across the battery (the terminal voltage) is 10 ~V , then the emf of the battery is

Step-by-step solution

The given situation is shown below If I= current in circuit then Where, gathered E-I r=V I=V / R gathered Here, given, aligned & R=8 & r=0.2 V=10 ~V aligned Hence, circuit current I= V R = 10 8 = 5 4 ~A Now, from eq. (i) with values we have, E=V+I r=10+ 5 4 0.2=10+0.25=10.25 ~V