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AP EAMCET20227 Jul 2022Morning ShiftPhysicsCurrent ElectricityActual

Two wires A and B of same material having length L_A, L_B and radii R_A, R_B and drift velocity v_A, v_B respectively carries same current. If L_A=L_B and R_A=2 R_B then the value of ( v_A v_B ) is

Options

  1. A0.25
  2. B0.5
  3. C2.0
  4. D1.0

Correct answer

A. 0.25

Step-by-step solution

Current through a wire is given by I=n e v_d A=n e v_d R^2 Here, n = number density of free charge carriers v_d= drift speed of electrons R= radius of wire e= charge on an electron Here, for two wires A and B aligned & I_A=I_B (given) & n_A=n_B (wires have same material) aligned R_A=2 R_B (given) so we have, I_A=I_B n e v_A R_A^2=n e v_B R_B^2 array ll & v_A v_B = ( R_B R_A )^2= ( R_B 2 R_B )^2 & v_A v_B = 1 4 =0.25 array

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