AP EAMCET20226 Jul 2022Morning ShiftPhysicsCurrent ElectricityActual
In the given figure: V ₁= V , V ₂= V , R ₁= R , R ₂= R , where , , and are positive real numbers. The value of current I is
Options
- A( -1) 4 ( + ) V R
- B( -1) 4 V R
- C( -1) 2 ( + ) V R
- D( -1)( + ) 2 V R
Correct answer
A. ( -1) 4 ( + ) V R
Step-by-step solution
By Mesh law Loop 1: i₁ R₁+ (i₁-i₂ ) R₂+V₂+i₁ R₁-V₁=0 i ₁ R + ( i ₁- i ₂ ) R + V + i ₁ R - V =0...(i) Loop 2: i₂ R₁+V₂+i₂ R₁-V₂+ (i₂-i₁ ) R₂=0 i ₂ R + V ₂+ i ₂ R - V ₂+ ( i ₂- i ₁ ) R =0 2 i ₂ R + ( i ₂- i ₁ ) R =0...(ii) Solving (i) & (ii), we get i ₂= -( -1) 4 ( - ) _ V R As I =- i ₂ So, I= ( -1) 4 ( + ) V R