AP EAMCET20225 Jul 2022Morning ShiftPhysicsCurrent ElectricityActual
In the given circuit values of I₁, I₂, I₃ are respectively
Options
- A1.364 ~A , 6.278 ~A , 5.91 ~A
- B1.97 ~A , 3.56 ~A , 2.784 ~A
- C-0.327 A, 5.28 A, 3.197 A
- D1.523 ~A , 4.396 ~A , 1.63 ~A
Correct answer
A. 1.364 ~A , 6.278 ~A , 5.91 ~A
Step-by-step solution
The given circuit diagram is shown as : Applying KVL in loop A B D A , we get 2 I₁+4-I₂=0I₂=2 I₁+4 ...(i) Applying KVL in loop B C D B , we get 1 (I₁+I₃ )-4 (I₂-I₃ )-4=0 array lr & I₁+I₃-4 I₂+4 I₃-4=0 & I₁+5 I₃-4 (2 I₁+4 )-4=0 array -7 I₁+5 I₃=20 I₃= 20+7 I₁ 5 ...(ii) By applying KVL in loop A D C A , we get I₂+4 (I₂-I₃ )-10=0 5 I₂-4 I₃=10 5 (2 I₁+4 )-4 ( 20+7 I₁ 5 )=10 [From Eqs. (i) and (ii)] I₁=1.364 ~A From Eq. (i), I₂=2 1.364+4=6.278 ~A From Eq (ii), I₃= 20+7 1.364 5 =5.91 ~A