AP EAMCET20224 Jul 2022Evening ShiftPhysicsCurrent ElectricityActual
The current ' i ' in the circuit shown in the figure is
Options
- Aε 2 R
- B- ε R
- C2 ε R
- D- 2 ε R
Correct answer
A. ε 2 R
Step-by-step solution
In the given question, Resistance in series with 2 ε is not given, assuming it to be R . The above circuit can be redrawn as, Using equivalent battery for the dotted portion shown in the figure below, ε e q = ε R + 2 ε R 1 R + 1 R = 1 . 5 ε and R e q = R 2 . Therefore, i = 3 - 1 . 5 ε 2 . 5 + 0 . 5 R = ε 2 R