AP EAMCET202125 Aug 2021Morning ShiftPhysicsCurrent ElectricityActual
A silver wire of length 3 ~m and of cross-sectional area 6.14 10⁻⁶ ~m ^2 carries a current of 6 A. Atomic weight and density of silver are 108 and 10500 kgm ⁻³ , respectively. A silver atom contributes one free electron for conduction. Avogadro number is 6.023 10²³ / mol . Drift velocity of electrons in silver is, close to
Options
- A10⁻² ~ms ⁻¹
- B10⁻⁴ ~ms ⁻¹
- C0.1 ~ms ⁻¹
- D1 ~ms ⁻¹
Correct answer
C. 0.1 ~ms ⁻¹
Step-by-step solution
Given, length of wire, l=3 ~m Cross-sectional area, A=6.14 10⁻⁶ ~m ^2 Current in the wire, I=6 ~A Atomic weight of silver =108 amu Density of silver, =10500 kgm ⁻³ aligned Number of electrons per kg of silver & =N_A / 108 & = 6.023 10²³ 108 aligned Number of electrons per unit volume of silver. n= 6.023 10²³ 108 10500 Drift current, I= Anev _d where v_d is drift velocity and n is number of electrons per unit volume. aligned & v_d= I n e A & = 6 108 6.023 10²³ 10500 1.6 10⁻¹⁹ 6.14 10⁻⁶ & =0.1 ~ms ⁻¹ aligned