Number of electrons flowing per second in a conductor carrying a current of 9 ~A is

Step-by-step solution

Given that, electric current, I=9 ~A Let n be the number of electron passing through a conductor in time t . We know that, I= q t and q=n e aligned & & I= n e t & n t & = I e aligned Substituting the values, we get Number of electron flowing per second, n t = 9 1.6 10⁻¹⁹ =5.6 10¹⁹ electrons per second.