AP EAMCET201921 Apr 2019Evening ShiftPhysicsCurrent ElectricityActual
In the given circuit, the electric currents through 15 Ω and 6 Ω respectively are
Options
- A0   A , 0 . 5   A
- B0   A , 1   A
- C0 . 5   A , 1   A
- D1   A , 0   A
Correct answer
A. 0   A , 0 . 5   A
Step-by-step solution
The figure below represents the given circuit. Apply Kirchhoff voltage law in loop I, - 9 + 6 I 1 + 12 I 1 + I 2 = 0 18 I 1 + 12 I 2 = 9 6 I 1 + 4 I 2 = 3       . . . . 1 Apply Kirchhoff law in loop II. - 6 + 15 I 2 + 12 I 1 + I 2 = 0 12 I 1 + 27 I 2 = 6 4 I 1 + 9 I 2 = 2       . . . . 2 From equation 1 and 2 , I 1 = 0 . 5   A I 2 = 0