In the circuit shown, if the current through the resistor R is 1 5 ~A , the value of R is

Step-by-step solution

According to the question, aligned & Now, equivalent emf, = V₁ R₁ - V₂ R₂ 1 R₁ + 1 R₂ & e= 5 2 - 2 1 1 2 + 1 1 = 1 3 ~V aligned Internal resistance, r= R₁ R₂ R₁+R₂ array rlrl & r & = 2 1 2+1 = 2 3 Current, & I & = e r+R or 1 5 = 1 3 2 3 +R & & 1 5 & = 1 3 2+3 R 3 & & 1 5 & = 3 3(2+3 R) & & 9 R & =15 & & 9 R & =15-6 or & & & =9 = & & 1 array