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AP EAMCET201920 Apr 2019Morning ShiftPhysicsCurrent ElectricityActual

The ratio of heats generated through shunt and galvanometer is (7: 5 ) when they are connected to make an ammeter. If the resistance of the galvanometer is (112 ) then the resistance of the shunt is

Options

  1. A(80 )
  2. B(8 )
  3. C(15.6 )
  4. D(1.56 )

Correct answer

A. (80 )

Step-by-step solution

Given, the ratio of heats generated through the shunt and galvanometer is (7: 5 ), and resistance of galvanometer, (R_g=112 ) ( Heat generated through shunt (p_s ) Heat generated through galvanometer (p_g ) = 7 5 ) ( aligned & V^2 R_s V^2 R_g = 7 5 ( p_S= V^2 R_S and p_g= V^2 R_g ) & R_s= 5 7 R_g R_s= 5 7 112=80 aligned ) Hence, the resistance of shunt, (R_s=80 )

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