If the charge on the capacitor is 1 mC in the given circuit, then R₁ R₂ R₃ = . . . . .

Step-by-step solution

Charge on cap =1 mC V _ capacitor = Q C = 1 10⁻³ 5 10⁻⁶ = 1000 5 =200 ~V So, current through R₅ I= V R = 200 10 =20 ~A Hence, we have following current distribution. In loop B C D B , In loop A B C D A , aligned & -200-15 R₃+50+250=0 & 15 R₃=100 R₃= 100 15 aligned From Eq. (i), we get 5 R₂=50 R₂=10 and from loop A D C A , aligned & -250-50+310-25 R₁=0 & 25 R₁=10 R₁= 10 25 aligned So, R₁ R₂ R₃ = 10 25 10 ( 100 15 ) = 15 25 = 3 5 =0.6